intial workup

README.md

@@ -0,0 +1,23 @@
+Create a function taking a positive integer as its parameter and returning a string containing the Roman Numeral representation of that integer.
+
+Modern Roman numerals are written by expressing each digit separately starting with the left most digit and skipping any digit with a value of zero. In Roman numerals 1990 is rendered: 1000=M, 900=CM, 90=XC; resulting in MCMXC. 2008 is written as 2000=MM, 8=VIII; or MMVIII. 1666 uses each Roman symbol in descending order: MDCLXVI.
+
+**Example:**
+```rust
+solution(1000); // should return 'M'
+```
+**Help:**
+
+```
+Symbol    Value
+I          1
+V          5
+X          10
+L          50
+C          100
+D          500
+M          1,000
+```
+Remember that there can't be more than 3 identical symbols in a row.
+
+More about roman numerals - http://en.wikipedia.org/wiki/Roman_numerals

src/main.rs

@@ -1,3 +1,41 @@
+#![allow(unused)]
 fn main() {
-    println!("Hello, world!");
+
+    let args = vec![
+        182,
+        1990,
+        1875,
+    ];
+
+    println!();
+
+    for arg in args {
+        println!("{:4} | {:?}", arg, func(arg));
+    };
+
+    println!();
+}
+
+fn func(num: i32) -> String {
+    let mut out = vec![];
+    let mut stack = vec![
+        (1, "I"), (4, "IV"), (5, "V"), (9, "IX"),
+        (10, "X"), (40, "XL"), (50, "L"),
+        (90, "XC"), (100, "C"), (400, "CD"),
+        (500, "D"), (900, "CM"), (1000, "M"),
+    ];
+
+    let mut num = num;
+
+    while let Some(div) = stack.pop() {
+        while num/div.0 > 0 {
+            out.push(div.1);
+            num -= div.0;
+        } 
+        if num == 0 {
+            break
+        }
+    }
+
+    out.join("")
 }